4[5y-(y-1)]=7(y-2)

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Solution for 4[5y-(y-1)]=7(y-2) equation:


Simplifying
4[5y + -1(y + -1)] = 7(y + -2)

Reorder the terms:
4[5y + -1(-1 + y)] = 7(y + -2)
4[5y + (-1 * -1 + y * -1)] = 7(y + -2)
4[5y + (1 + -1y)] = 7(y + -2)

Reorder the terms:
4[1 + 5y + -1y] = 7(y + -2)

Combine like terms: 5y + -1y = 4y
4[1 + 4y] = 7(y + -2)
[1 * 4 + 4y * 4] = 7(y + -2)
[4 + 16y] = 7(y + -2)

Reorder the terms:
4 + 16y = 7(-2 + y)
4 + 16y = (-2 * 7 + y * 7)
4 + 16y = (-14 + 7y)

Solving
4 + 16y = -14 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
4 + 16y + -7y = -14 + 7y + -7y

Combine like terms: 16y + -7y = 9y
4 + 9y = -14 + 7y + -7y

Combine like terms: 7y + -7y = 0
4 + 9y = -14 + 0
4 + 9y = -14

Add '-4' to each side of the equation.
4 + -4 + 9y = -14 + -4

Combine like terms: 4 + -4 = 0
0 + 9y = -14 + -4
9y = -14 + -4

Combine like terms: -14 + -4 = -18
9y = -18

Divide each side by '9'.
y = -2

Simplifying
y = -2

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